My Report

Engineering Physics I Practice Test 6


Correct Answer: 2 points | Wrong: -1 point
Grades: A* (100% score) | A (80%-99%) | B (60%-80%) | C (40%-60%) | D (0%-40%)
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1. Statement: In simple harmonic motion, the motion is to and fro and periodic.
Reason: Velocity of the particle,
v=ω√(a2-x2)
Where x is displacement.

2. The total energy of a particle performing simple harmonic motion depends on ___________

3. The time period of a simple pendulum on a satellite, orbiting around the earth, is ___________

4. Two bodies M and N of equal masses are suspended from separate massless spring of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of variation of M to that of N is?

5. Every simple harmonic motion is periodic motion, but every periodic motion need not be simple harmonic motion.

6. A particle is executing simple harmonic motion at midpoint of mean position and extremely. What is the potential energy in terms of total energy (E)?

7. The maximum velocity of a particle, executing simple harmonic motion with amplitude 7mm, is 4.4m/s. The period of oscillation is?

8. A simple pendulum has a time period T1, when on the earth’s surface; and T2, when taken to a height R above the earth’s surface (R is the radius of the earth). The value of T2/T1 is?

9. The mass and the radius of a planet are twice that of earth. Then, period of oscillation of a second pendulum on that planet will be ___________

10. The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2×10-2 cosπt(in m). The time at which the maximum speed first occurs is?


 

Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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