My Report

Heat Transfer Practice Test 2


Correct Answer: 2 points | Wrong: -1 point
Grades: A* (100% score) | A (80%-99%) | B (60%-80%) | C (40%-60%) | D (0%-40%)
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1. Suppose heat is conducted due to electrons
Where, i = I/A and p is the resistivity, then

2. The general solution of linear and homogenous differential equation (second form) is of the form

3. A steel rod (k = 30 W/m degree) 1 cm in diameter and 5 cm long protrudes from a wall which is maintained at 10 degree Celsius. The rod is insulated at its tip and is exposed to an environment with h = 50 W/m2 degree and t a = 30 degree Celsius. Calculate the rate of heat dissipation

4. The maximum temperature for cylindrical coordinate occurring at r = 0 is

5. In case when both the surfaces of plane wall are at different temperature, we get an expression i.e.
T MAX – T W2 /T W1 – TW2 = (B + 1)2/4B
What is the value of B?

6. “All the factors relating to the geometry of the sections are grouped together into a multiple constant called the shape factor”.

7. The oven of an electric store, of total outside surface area 2.9 m2 dissipates electric energy at the rate of 600 W. The surrounding room air is at 20 degree Celsius and the surface coefficient of heat transfer between the room air and the surface of the oven is estimated to be 11.35 W/m 2 degree. Determine the average steady state temperature of the outside surface of the store
heat-transfer-questions-answers-conduction-sphere-q10

8. Which is true regarding a complete rectangular furnace?

9. In case of heat conduction through the plane wall, which one of the following is not a correct assumption?

10. Find the value of corrected length for rectangular fin?
Where, b is width and t is length of the fin


 

Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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