Network Theory Practice Test 6

1. The value of ‘c’ in complementary function of ‘i’ is?

c = V/R cosθ+V/√(R²+(1/(ωC))²) cos⁡(θ+tan^-1(1/ωRC))

c = V/R cosθ-V/√(R²+(1/(ωC))²) cos⁡(θ+tan^-1(1/ωRC))

c = V/R cosθ-V/√(R²+(1/(ωC))²) cos⁡(θ-tan^-1(1/ωRC))

c = V/R cosθ+V/√(R²+(1/(ωC))²) cos⁡(θ-tan^-1(1/ωRC))

2. For the function F (s) = (s+5)/s(s²+2s+5), after splitting this function into the partial fractions, the co-efficient of 1/(s+1-j2) is?

-1/4

1/2

1/4

-1/2

3. In the circuit given below, the current source is 1∠0° A, R = 1 Ω, the impedances are Z_C = -j Ω and Z_L = 2j Ω. The Thevenin equivalent looking across A-B is __________

\(\sqrt{2}\)∠45° V, (1+j) Ω

2∠45° V, (1+j) Ω

\(\sqrt{2}\)∠0 V, (1+2j) Ω

2∠45° V, (1-2j) Ω

4. If the roots of an equation are complex conjugate, then the response will be?

damped

critically damped

under damped

over damped

5. The total period of the function shown in the figure is 4 sec and the amplitude is 10. Find the function f₁ (t) from t = 0 to 1 in terms of unit step function.

10t [u (t) – u (t + 1)]

10t [u (t) + u (t + 1)]

10t [u (t) + u (t - 1)]

10t [u (t) – u (t - 1)]

6. Let us assume x (t) = A cos(ωt + φ), what is the value of k₁?

H(jω)Ae^jØ

H(jω)Ae^-jØ

1/2 H(jω)Ae^-jØ

1/2 H(jω)Ae^jØ

7. The expression of current from the circuit shown below is?

i=2(1+e^2t)A

i=2(1-e^-2t)A

i=2(1+e^-2t)A

i=2(1+e^2t)A

8. If the roots of an equation are real and unequal, then the response will be?

damped

under damped

over damped

critically damped

9. Find the function f₂ (t) from the time t = 1 to 3 sec.

(-10t-20) [u (t-1) – u (t-3)]

(-10t+20) [u (t-1) +u (t-3)]

(-10t+20) [u (t-1) – u (t-3)]

(-10t-20) [u (t-1) + u (t-3)]

10. The transfer function of a system having the input as X(s) and output as Y(s) is?

Y(s) * X(s)

Y(s) + X(s)

Y(s) – X(s)

Y(s)/X(s)